Thread: problem with PHP stoping half way

I have this code and when I search a valad term It works but if what im searching dosent exist I want it to show the error message but if there are no results the php just stops and ignores the rest of the code

Code:

<h2>Search</h2> 
<form method="post" action="<?=$PHP_SELF?>">
Seach for: <input type="text" name="find" />
<input type="hidden" value="id"
<input type="hidden" name="searching" value="yes" />
<input type="submit" name="search" value="Search" />
</form>


<?
//first of having the double / makes this line of text be ignored by the server.
//these are called comments and they serve no purpous to the html thats is sent to the users browser
//extra empty line breaks do nothing ether. although they are included in the line count as well as comments
 
//this makes $find= what was entered into the search box
$find=$_POST["find"];

//this makes $searching the value of the hidden field searching which
// is only used to hide this part untill you enter a search
$searching=$_POST["searching"];

//This is only displayed if they have submitted the form 
//this is the purpous of the hidden field searching
//the rest of the code for the results is contained in here
if ($searching =="yes") 
{ 
echo "<h2>Results</h2><p>"; 

//If they did not enter a search term we give them an error. 
//notice the 'if' if $find = nothing then run whats within the following {}
//and exit makes the PHP stop there and not go on.
//if the 'if' is not true it moves past the {}
if ($find == "") 

{ 
//echo will display the text in the "" or the result on an array for example $find
echo "<p>Please Enter An Error Code"; 
exit; 
} 

// Otherwise we connect to our Database (host, username, password) or die tells the code to show a php error
mysql_connect("******", "******", "******") or die(mysql_error()); 
// once logged onto the DB this selects the specific DB set in my case its the same as my user name
mysql_select_db("******") or die(mysql_error()); 

// We preform a bit of filtering 
// $find is what you typed into the search bar. 
// these 3 lines make it all uppercase, strips any code, and removes spaces
$find = strtoupper($find); 
$find = strip_tags($find); 
$find = trim ($find); 

//Now we search for our search term supplied in the search box.
// this will make the results of the search be accessable as $data
// FROM= the table, WHERE= the colum, and the '=' means the row that has the search term in the ID colum
$data = mysql_query ("SELECT * FROM dmx WHERE ID LIKE '$find'");


//And we display the results 
//This turns the $data (which is only a code for the row on the table) into useable text.
$info = mysql_fetch_array ( $data ) or die(mysql_error());
 { 

//this will show the word 'code:' followed by what ever was in the search box
echo "<b>Code:</b> " .$find. "<br>";

//this uses the results from the database row defined by $info and the colum data
//$info= row ['data']= colum.
echo "<b>Description:</b> " .$info['data']. "<br>"; 
} 

//This counts the number or results - and if there wasn't any it gives them a little message explaining that 
//still trying to get this to work

//this counts the nuber of rows which = $anymatches
$anymatches = mysql_num_rows($data);
if ($anymatches == "0") { 
echo "Sorry, no results. (be sure you have the whole error code)<br><br>"; 
echo "<b>Searched For:</b> " .$find; 
} 

}
?>

sorry about the extra comments. using this as an example for a friend who is jut starting. I'm pretty new myself.

Take a look at this sample script: Using PHP to search a MySQL database and return paged results

Also, the browser you use won't make a difference when it comes to server-side code.